How to use #[ts(export_to = "")]?

[yujonglee]

How to use #[ts(export_to = "")]?

[NyxCode]

You need #[ts(export)], as well as #[ts(export_to = "pkg/bindings/")]:

#[derive(Serialize, Clone, TS)]
#[ts(export, export_to = "pkg/bindings/")]
pub struct Node {
}

export generates a test which does the exporting, export_to sets the output path.

[yujonglee]

@NyxCode Now I got it. Thank you so much. 👍

[NyxCode]

Hey @yujong-lee,
if you want to export to a specific file, you can do #[ts(export_to = "path/to/file")].
If you want to export to a directory, you can do #[ts(export_to = "path/to/directory/")] (notice the trailing /).
I'll clarify this further in the docs.

[yujonglee]

@NyxCode

.
├── Cargo.toml
├── bindings
├── pkg
│   └── bindings
├── src
│   ├── graph
│   │   ├── types.rs

I have many #[ts()] macros is in src/graph/types.rs like below.

#[derive(Serialize, Clone, TS)]
#[ts(export)]
pub struct Node {
}

Default output is bindings. I want pkg/bindings to be output path.

Then isn't #[ts(export_to = "pkg/bindings/")] correct?

#[derive(Serialize, Clone, TS)]
#[ts(export_to = "pkg/bindings/")]
pub struct Node {
}

Currently, it doesn't works for me. (And #[ts(export_to = "../pkg/bindings/")] too.)