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rozek avatar rozek commented on July 17, 2024

Ah, I got s.th.:

  • since Gun merges new values with existing ones, setting {} simply merges nothing - i.e., it leaves the existing object unchanged and, thus, does not invoke the event handler
  • what still surprises me, however, is the observation that the code
  const sharedData = Gun.get('sharingTest').get('sharedData')
    sharedData.put({})
  sharedData.on((Data) => { console.log('sharedData: "' + JSON.stringified(Data) + '"') })

sometimes writes onto the console, sometimes it doesn't (that's why I currently use this approach in my experiments in order to avoid the event handler being called initially, i.e., after loading previous contents from localStorage - which works most of the time...) are these "race conditions"?

Sorry for bothering you!

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rozek avatar rozek commented on July 17, 2024

I'm completely lost...

what I did:

  • const sharedData = Gun.get('sharingTest').get('sharedData')
  • sharedData.put({ a:'a' }) - works
  • waiting for completion using a "once" event handler - works
  • sharedData.put(null) - works
  • waiting for completion using a "once" event handler - works
  • sharedData.put({ b:'b' }) - works
  • waiting for completion using a "once" event handler - oops

the last step shows that the previous contents (namely { a:'a' }) reappear again - although I previously successfully overwrote the node with a primitive!

How can that be? I am not yet using any relay - everything works locally only (albeit with "localStorage" in the background, if I understood the concepts correctly)

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amark avatar amark commented on July 17, 2024

{} is an empty set, so if it is merging into an existing object then no actual change occurs, however I do believe the lower level events get fired, but .on( etc. dedups it.

if you overwrite something with a primitive, then re-save an object to it... it'll re-generate the same deterministic soul on that path, thus it'll "re-find" the old data.

var newNode = gun.get("randomID").put({b: 'b'}); sharedData.put(newNode); will force a different node onto it, overwriting the previous and NOT re-merging with a previous node. But note: This can lead to disparity in offline apps if this happens a lot, as offline apps might not generate the same "location" to converge too.

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rozek avatar rozek commented on July 17, 2024

Thank you very much for your explanation.

However, I somewhere found the "recipe" to first nullify an object and then to write a new one using the same context (I have to find where, but I'm really lost in the jungle of overlapping doc sections and wiki pages...). This recipe would contradict your explanation then.

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