Dictionary value cannot be recruited as template

[antlr]

Dictionary value cannot be recruited as template

[parrt]

try field not field=field

[phreed]

That works.
Similarly

auxMap ::= [
   "E": "electric <field>",
   "I": "in <field> between",
   "F": "<field> force",
   default: "<field>"
]

makeTmpl(type, field) ::= <<
<auxMap.(type)>
>>

top ::= <<
  <makeTmpl("E", "foo")>
  <makeTmpl("F", "foo")>
  <makeTmpl("I", "foo")>
>>

Would previously result in...

electric foo
foo force
in foo between

Now this produces three blank lines.
Is this the correct behavior?
I'm guessing it is deprecated.

[parrt]

I'll have to look into that one. should work.

[sharwell]

What happens if you use the following dictionary?

auxMap ::= [
   "E": {electric <field>},
   "I": {in <field> between},
   "F": {<field> force},
   default: {<field>}
]

[phreed]

Yes, that works.
The new syntax makes more sense, it looks more like a dictionary of anonymous templates (and not just a bunch of strings).
I guess these aren't bugs, just operator error (or maybe a soft spot in the documentation?).
As relating to documentation I noticed that in some cases the '}' needs to be escaped in v4.
e.g.

<foo: { bar |  then we put in some source containing \} that needs escaping }; separator="," >

Thanks

[parrt]

top ::= <<...

should be

top() ::= <<...

As indicated by the reported error message:

t.stg 12:0: garbled template definition starting at 'top'

With that in place, the expected (and actual) text output is:

  electric <field>
  <field> force
  in <field> between