Comments (6)
For using strings methods you need to override callexpression and provide the funciton manually. For example parseAsString(24)
from expressions.
Yes, that I am aware. My problem is I want the parser to be able to handle string directly in the expression. I that possible?
Instead of image 1, do it as image 2.
from expressions.
@danielweil '2'.days doesnt make any sense. See the expression parsing is failing at 24 char
from expressions.
It is a method I created. If it was any other in dart language, is there any way that it would work?
For instance,
"2 ".trim()
What about the parseAsString(24) you told me above, can you be a bit more clear? Do I have to implement this in a custom class? Like "x.parseAsString(24)", {'x': CustomClass}?
from expressions.
class ResponseEvaluator extends ExpressionEvaluator {
const ResponseEvaluator();
@override
dynamic evalCallExpression(
CallExpression expression,
Map<String, dynamic> context,
) {
if (expression.callee is Variable &&
(expression.callee as Variable).identifier.name == "roundOff") {
final arguments =
expression.arguments.map((e) => eval(e, context)).toList();
return Function.apply(roundOff, arguments);
} else if (expression.callee is Variable &&
(expression.callee as Variable).identifier.name == "subtractDates") {
final arguments =
expression.arguments.map((e) => eval(e, context)).toList();
return Function.apply(subtractDates, arguments);
} else if (expression.callee is Variable &&
(expression.callee as Variable).identifier.name == "toString") {
final arguments =
expression.arguments.map((e) => eval(e, context)).toList();
return Function.apply(convertToString, arguments);
} else if (expression.callee is Variable &&
(expression.callee as Variable).identifier.name == "toDouble") {
final arguments =
expression.arguments.map((e) => eval(e, context)).toList();
return Function.apply(convertToDouble, arguments);
}
return super.evalCallExpression(expression, context);
}
}
@danielweil See how i created custom methods for utilising string methods. Note you cant access string methods directly here because. expression wont evaluate.
to use above methods toString(23)
from expressions.
Thanks! That cleared all my doubts!
from expressions.
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from expressions.