Comments (5)
function hehe(str) {
if (str.length == 0) return '';
var map = {};
var maxLen = 1;
var maxChar = str[0];
for (var i = 0; i < str.length; i++) {
var char = str[i];
if (map[char] != null) {
if (i - map[char] + 1 > maxLen) {
maxLen = i - map[char] + 1;
maxChar = char;
}
} else {
map[char] = i;
}
}
return str.slice(map[maxChar], map[maxChar] + maxLen);
}
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function hehe(str) { if (str.length == 0) return ''; var map = {}; var maxLen = 1; var maxChar = str[0]; for (var i = 0; i < str.length; i++) { var char = str[i]; if (map[char] != null) { if (i - map[char] + 1 > maxLen) { maxLen = i - map[char] + 1; maxChar = char; } } else { map[char] = i; } } return str.slice(map[maxChar], map[maxChar] + maxLen); }
每次看你代码我都想哭T﹏T😭
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基本思路:
用一个hashmap去存储每一个字符第一次出现位置,遍历过程中如果当前字符出现过,算出当前长度 判断是否最长
代码:
function LES(str) {
const mapper = {};
let maxLen = 0;
let start = 0;
for(let i = 0; i < str.length; i++) {
const c = str[i];
// 存储每一个字符第一次出现位置
if (mapper[c] === void 0) {
mapper[c] = i;
} else if (i - mapper[c] > maxLen) {
// 更新最大值
start = mapper[c];
maxLen = i - mapper[c];
}
}
return str.slice(start, start + maxLen + 1)
}
from leetcode.
这个思路有问题吧 ?可以过么
from leetcode.
这个思路有问题吧 ?可以过么
说出你的想法
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