Comments (4)
What is the question?
from fatfree.
That's odd – there used to be a question which was:
$socket is assigned a value and then, in the next line, assigned the result of the stream_socket_client call. What I don't understand: Why assign it the address of this->socket first if it's not used? Maybe my understanding lacks here, sorry.
from fatfree.
What is the question?
It got edited out.
from fatfree.
The first assignment sets the variable as a reference to this->socket and the following assignment sets a new variable content (to both).
from fatfree.
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from fatfree.