Comments (3)
It may require to flatten the root node and pass openAllNodes=true
as its parameter to return new nodes when calling filter
:
filter(predicate, options) {
: : :
traverse(rootNode);
this.nodes = flatten(rootNode.children, {
openAllNodes: true // open all nodes
});
// Update rows
this.rows.length = this.nodes.length;
for (let i = 0; i < this.nodes.length; ++i) {
const node = this.nodes[i];
this.rows[i] = this.options.rowRenderer(node, this.options);
}
this.update();
}
To revert back to previous open state when calling unfilter
, flatten the root node again with openNodes
state:
unfilter() {
: : :
traverse(rootNode);
this.nodes = flatten(rootNode.children, {
openNodes: this.state.openNodes // open only desired nodes
});
// Update rows
this.rows.length = this.nodes.length;
for (let i = 0; i < this.nodes.length; ++i) {
const node = this.nodes[i];
this.rows[i] = this.options.rowRenderer(node, this.options);
}
this.update();
}
from infinite-tree.
Not verified whether it will work or not, I will let you know the result when I have time to make a complete test.
from infinite-tree.
I just tried the code and it worked just like desired. Many thx!
I needed to adjust the following a bit:
I used _flattree.flatten(rootNode.children, { ....
because flatten()
seemed to be undefined
from infinite-tree.
Related Issues (20)
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from infinite-tree.