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flyman3046 avatar flyman3046 commented on May 20, 2024

I think in algebra a vector is generally referring to a column vector. So w_j is a column vector (with D elements) after reshaping j-row of W. And by convention, w_j^T x_i will give a real number. Check out section 1.1 and 2.1 in http://cs229.stanford.edu/section/cs229-linalg.pdf.

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nizza avatar nizza commented on May 20, 2024

I think there's a typo. In order to obtain a scalar the first operand must have size (1,k) and the second must have size (k,1).
So the row vector w_j must not be transposed.

from cs231n.github.io.

xuweichn avatar xuweichn commented on May 20, 2024

there was a comment: where w_j is the j-th row of W reshaped as a column, means that w_j is a column vector which is reshaped from the j-th row of W.

I was confused by this point by weeks. Intuitively, I think the w_j is the j-th row of W. I still think the way of dealing with the vector is meaningless.

from cs231n.github.io.

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