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byby221b avatar byby221b commented on May 3, 2024

13.6 公式推导有笔误

公式13.6关于LL(D_l)的推导中,最后一步求和符号下面x_j的范围写错了,望更正。

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byby221b avatar byby221b commented on May 3, 2024

(此处应为D_l而非D_t

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Sm1les avatar Sm1les commented on May 3, 2024

@byby221b 好的,感谢您的反馈,我已经通知了13章的负责人进行修订,如果您还发现了其他问题,还烦请持续反馈 :)

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LeoLRH avatar LeoLRH commented on May 3, 2024

@byby221b 你好我仔细看了您说的两个问题,都是我的笔误推导写错了,收到我已更正

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byby221b avatar byby221b commented on May 3, 2024

@LeoLRH
好的,非常感谢你们的工作

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LeoLRH avatar LeoLRH commented on May 3, 2024

@Sm1les 麻烦负责人看一下这个问题,我的文档上是没有这个问题的可能上次该文档时出现了纰漏,看看是Markdown代码的问题还是格式转换的问题,麻烦啦

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LeoLRH avatar LeoLRH commented on May 3, 2024

公式13.6有小错误
image

谢谢您的反馈,已经再更改中

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dinger0 avatar dinger0 commented on May 3, 2024

这是我整理的其他小问题
image

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Sm1les avatar Sm1les commented on May 3, 2024

@Admin2B 好的,感谢您的反馈,我们尽快修正过来 :)

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OriginPrince avatar OriginPrince commented on May 3, 2024

您好,13.5 均值初始化的公式好像有点问题,谢谢。

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archwalker avatar archwalker commented on May 3, 2024

您好,13.5 均值初始化的公式好像有点问题,谢谢。

您好,这里是typo,已修复,感谢反馈

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ChenZQ-nano avatar ChenZQ-nano commented on May 3, 2024

关于公式 13.21,我查了原文献,这个式子的最优解就是13.20,
请问(1)为什么要进行迭代,是为了避免直接求逆吗,这种避免求逆的算法有名字吗,是不是以后遇到这种问题都可以这样迭代。
(2)另外13.21的第一项在Fi前除以了i的度,这是要将数据点的密度因素也考虑进来的意思(也就是越相似的数据点,他们的度也一样)吗

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archwalker avatar archwalker commented on May 3, 2024

关于公式 13.21,我查了原文献,这个式子的最优解就是13.20,
请问(1)为什么要进行迭代,是为了避免直接求逆吗,这种避免求逆的算法有名字吗,是不是以后遇到这种问题都可以这样迭代。
(2)另外13.21的第一项在Fi前除以了i的度,这是要将数据点的密度因素也考虑进来的意思(也就是越相似的数据点,他们的度也一样)吗

(1) 13.4节开头交代了采用“迭代算法”的背景,即半监督学习对应于标签在图上的传播过程,这个传播过程即是迭代计算并达到稳态的过程。这种算法就叫标签传播(label propagation)
(2) 是,可以理解成对图中热点节点的规范化。

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ChenZQ-nano avatar ChenZQ-nano commented on May 3, 2024

您好,我的第一个问题意思是:既然标签传播是从13.21的目标函数优化得到的,但是这个问题有解析解啊,也就是13.2,那有解析解为什么还要迭代

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archwalker avatar archwalker commented on May 3, 2024

您好,我的第一个问题意思是:既然标签传播是从13.21的目标函数优化得到的,但是这个问题有解析解啊,也就是13.2,那有解析解为什么还要迭代

方阵S的维度是N*N,其中N是图中节点的数量,如此大的矩阵求逆很困难。

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zceolrj avatar zceolrj commented on May 3, 2024

公式13.15是 $f_u = (D_{uu} - W_{uu})^{-1}W_{ul}f_l $
公式13.17是 $f_u = (I - P_{uu})^{-1}P_{ul}f_l $

请问一下:这两个公式是不是都可以根据 $f_l$ 解出 $f_u $
如果都可以,为何还要从13.15再推导到13.17 ?

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