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demopark avatar demopark commented on May 14, 2024
Foo.findAll({
  include: [{
    model: Bar,
    through: {
      attributes: [/* 在此处列出所需的属性 */]
    }
  }]
});

对应

{
  "id": 1,
  "name": "foo",
  "Bars": [
    {
      "id": 1,
      "name": "bar"
    }
  ]
}

======

Foo.findOne({
  include: {
    model: Bar,
    attributes: []
  }
});

对应

{
  "id": 1,
  "name": "foo"
}

不需要联结表中的任何内容 直接attributes: []即可.不会带有任何Bar表的内容.

from sequelize-docs-zh-cn.

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