How to properly get Reel (Clip) from the given URL and download reel?

[yemreak]

How to properly get Reel (Clip) from the given URL and download reel?

[siyosu]

To get media info you need to pass the media id not the media code.
You can get media id using oembed https://i.instagram.com/api/v1/oembed/?url=<the post / reel url>

[yemreak]

Thank you so much @siyosu!

Here is the my necessary code scripts for who are planning to do similar actions

import fs from "fs"
import path from "path"

async function getIGMediaIdFromURL(url: string): Promise<string> {
	const response = await fetch(`https://i.instagram.com/api/v1/oembed/?url=${url}`)
	const data = await response.json()
	return data.media_id
}

export async function downloadFile(url: string, outputPath: string): Promise<void> {
	const response = await fetch(url)
	if (!response.ok) throw new Error(`Failed to download: ${response.statusText}`)

	const buffer = await response.arrayBuffer()
	fs.writeFileSync(outputPath, Buffer.from(buffer))
}

const mediaId = await getIGMediaIdFromURL(postUrl)
const mediaInfo: any = await ig.media.info(mediaId) // ig comes from "instagram-private-api"
const videoUrl: string = mediaInfo.items[0].video_versions[0].url

const output = path.join("data", `${mediaId}.mp4`)
await downloadFile(videoUrl, output)