Comments (3)
Hi Rafael,
Only updating the top reference doesn't remove the reference the old top (popped item) has to the new top
Can you point me to a link that discusses this further?
For reference, I believe this is the function we are discussing:
def pop(self):
if self.top is not None:
data = self.top.data
self.top = self.top.next
return data
return None
It is my understanding that:
- Python's garbage collector will automatically handle this without the need to "remove references from the node we want to pop".
- If this were C/C++ and that node were created with malloc/new then we should deallocate that memory.
-Donne
from interactive-coding-challenges.
Hi Donne, I misunderstood the way Python gc works. I was thinking that any reference pointing in or out the object would keep it alive, but it's not the case (only references to the object work for that matter).
from interactive-coding-challenges.
Sounds good, thanks Rafael :)
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