Comments (2)
@AkashBhave Just in case you're still wondering, ? propagates the error (if there is one) further up the chain (meaning that it would return at this point with the error) as your function seems to be a function which is actually for an end program you should probably either .unwrap() or handle the error in another way here. You could still do it by changing the return type of your function to a result which contains the error type of this library but it's questionable wether you actually want to do that.
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@hargoniX thanks for the help, I eventually got it cleared up by handling the error within the function.
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