Comments (3)
Permanent link for the code mentioned https://github.com/jhalterman/failsafe/blob/119c6c88a82df906134ab1b06459fe8bebdadaf0/src/main/java/net/jodah/failsafe/internal/util/CircularBitSet.java#L33
(won't change after a commit)
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Hi @na389 ,
Because CircularBitSet should keep latest execution result while the threshold size became smaller.
ex:
while CircularBitSet size changed from 10 to 4, the new CircularBitSet will only take the execution result from old bitSet from 6 to 10.
from failsafe.
@na389 I just pushed a commit that re-works this a bit, so hopefully it's clear now what's going on. The basic algo is:
- Determine how many bits to copy.
- Determine the index to start copying from.
- Loop and copy the bits. Since the data structure is circular, looping may require going back to
0
.
Since we want to copy the n
most recent bits, the start index is just the end of the logical bitset (nextIndex
) minus the number of bits to copy. But since the data structure is circular, if this number ends up being negative (when the number of bits to copy is greater than the nextIndex
), then we need to offset by the size of the bitset.
You can check out some of the test cases for this stuff which assert that BitSets values are copied as expected given various nextIndex
values (which may vary as the BitSet is circularly filled and refilled).
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