How can I print wlroots logging?

[flacjacket]

How can I print wlroots logging?

[flacjacket]

Do you have any examples you are looking at? If something goes to stdout, we could capture that, but I'm not sure there is a great way to selectively capture logging messages going to stdout and pass through other things that are going to stdout.

[flacjacket]

If you are looking to capture wlroots's logging, does running wlroots.util.log.log_init solve your problem? That should setup the wlr logging to callback into log_func_callback for logging.

[m-col]

If I stick print("hi") within log_func_callback then I see a lot of lines printed to stdout, as expected. I think what's happened is I was expecting a similar signature between:

void wlr_log_init(enum wlr_log_importance verbosity, wlr_log_func_t callback);

and

def log_init(log_level: int) -> None

I guess the intended usage is to use an interface exposed by the logging module to change where the messages end up?

[m-col]

This does it:

import logging
from wlroots.util.log import logger, log_init

class PrintHandler(logging.Handler):
    def emit(self, record):
        print(record)

logger.addHandler(PrintHandler())
log_init(logging.DEBUG)

[flacjacket]

Nice! Does something like this do the trick, too?

import logging
from wlroots.util.log import log_init

logging.basicConfig(level=logging.DEBUG)
log_init(logging.DEBUG)

[m-col]

Yep that works too, I'll use that, thanks.

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On 210523 04:11, Sean Vig wrote: Nice! Does something like this do the trick, too? ``` import logging from wlroots.util.log import log_init logging.basicConfig(level=logging.DEBUG) log_init(logging.DEBUG) ``` -- You are receiving this because you modified the open/close state. Reply to this email directly or view it on GitHub: #33 (comment)