Comments (1)
Thanks for bringing this up! I think the unclear bit is here:
In the prior task example,
assignments
was always a function in the function set[Tasks -> SUBSET CPUs]
.
If there are 3 CPUs, then S == SUBSET CPUs
would have 2^3 = 8
elements. Then #S^#Tasks = 8^2 = 64
.
Would I help if I added this to the tip?
.. tip:: A function set of form
[A -> B]
will have :math:\#B^{\#A}
elements in it. If there were two tasks and three CPUs, that would beCardinality([Tasks -> SUBSET CPUs]) =
:math:(2^3)^2 = 64
possible functions.
from learntla-v2.
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