Comments (6)
Hi, what Board are you using? I remember that for example I had a NodeMCU (ESP8266) board which had the builtin LED connected to VCC so that it was low active. So in your example you perhaps just see On()
and Off()
reversed. If this is the case, try to construct your led object like auto led = Jled(LED_BUILTIN).LowActive();
which will invert the output.
br
jan
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I checked your example and had the same problem ... In addition to what I have written in regards to low-active builtin LEDs above, there is another problem with the sketch: Every JLed effect has a duration/period. Using On()
or Off()
configures internally an effect with period of 1ms. So when you call Off()
after the delay(2000)
the JLed effect is already finished and nothing will happen. Solution:
- Instead of calling
led.Off().Update()
, callled.Stop()
to stop any effects and turn the LED off. This is the general approach to stop an effect and turn a LED off. - Alternatively reset and reconfigure the
led
object by callingReset()
:led.Reset().Off().Update()
. This approach can be used to assign a different effect to a JLed object.
Perhaps Reset()
should be always called when a new effect is assigned, I will think of making a change here.
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@jandelgado Thank you very much for your quickly response.
I have tested on Arduino UNO and ESP32. They have the same results. The builtin LED is high-active.
After many experiments, I also explored the solution, which is same with your solution 2.
But I think it is not simple enough. Looking forward to your optimization. :)
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Yes - I think so too. Will fix it the next days, stay tuned.
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New Release 4.2.0 addresses issue. Looking forward getting your feedback
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Verified release 4.2.0, it works as expected. Great job! 👍
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Related Issues (20)
- Blink twice HOT 2
- Evolution for non PWM pins HOT 2
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- times in millis should be 32bit values HOT 3
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