subscribe to end of a call

[jeansch]

subscribe to end of a call

[mouseratti]

Hello.
This code is very ugly, but it works for me.

def main():

   def hangup_handler(ami, event):
        dialstatus = event['DialStatus']
        if dialstatus in ('BUSY', ):
            channel = event['Channel']
            channel.Hangup()
        return

    logger.debug('O__0 main function was started  ;-)')
    while True:
        try:
            ami_listener = get_ami()
            ami_listener.events.subscribe('DialEnd', hangup_handler)
            break
        except Exception:
            logger.error(traceback.format_exc())
            sleep(5)

    while True:
        try:
            ami_listener.serve_forever()
        except Exception:
            logger.error(traceback.format_exc())
            ami_listener._connect()
            sleep(5)

if __name__ == '__main__':
    main()

I think you need to handle an action 'Hangup'

[dummys]

thanks for your snippet. Yes you are right, it's working with the Hangup event. Thanks a lot.