Convert MfArray back to regular Swift's Array with a specific type

[jjjkkkjjj]

Convert MfArray back to regular Swift's Array with a specific type

[jjjkkkjjj]

From now, you can get swift's Array with Int by toArray method of MfArray with MfType.Int like this;

let a = MfArray([[2, -7, 0],
                             [1, 5, -2]])
guard let swiftNdArray = a.toArray() as? [[Int]] else{ fatalError() }
print(swiftNdArray)
/*
[[ 2, -7,  0],
[ 1,  5, -2]]
*/

guard let swiftFlattenArray = a.flatten().toArray() as? [Int] else{ fatalError() }
print(swiftFlattenArray)
/*
[ 2, -7,  0,  1,  5, -2]
*/

[alwc]

Thanks @jjjkkkjjj !

[jjjkkkjjj]

@alwc
If you want N-dimensional array, use toArray function I just implemented.
e.g.)

let a = MfArray([[2, -7, 0],
                             [1, 5, -2]])
guard let swiftNdArray = a.astype(.Int32).toArray() as? [[Int32]] else{ fatalError() }
print(swiftNdArray)
/*
[[ 2, -7,  0],
[ 1,  5, -2]]
*/

Or, if you want flatten array, use flatten function and toArray like this

let a = MfArray([[2, -7, 0],
                             [1, 5, -2]])
guard let swiftFlattenArray = a.astype(.Int32).flatten().toArray() as? [Int32] else{ fatalError() }
print(swiftFlattenArray)
/*
[ 2, -7,  0,  1,  5, -2]
*/