Comments (5)
Uhh you mean like this
import rx._
val a = Var(1); val b = Var(2)
val c = Rx{ a() + b() }
println(c()) // 3
a() = 4
println(c()) // 6
from scala.rx.
What I meant is
import rx._
val f = (a: Int, b: Int) => a + b
val f1 = Fun(f)
val a = Var(1); val b = Var(2)
val c = Rx{ f1(a, b) }
println(c()) // 3
a() = 4
println(c()) // 6
f can be any function I want to re use. I don't see why you closed this.
from scala.rx.
I closed it because it already works. Did you even try it?
from scala.rx.
Not yet. I was going through the docs. It was silent on how to integrate existing code in the middle of a dataflow. I thought this did not exist. Any way the initial code you have given above also does not show how to pipe variable a and b into an existing function keep passing this into other rx variables which might be other functions.
from scala.rx.
Well, go try it, it works. At least try out the features which exist before making a feature request!
from scala.rx.
Related Issues (20)
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from scala.rx.