Problems with non-zero-based names

[ljharb]

Problems with non-zero-based names

[nlf]

That's because by default qs is creating a sparse array and placing the members in the correct indices, it then compacts that array preserving order, thus:

Qs.parse('obj[2]=value2&obj[1]=value1');

will yield

{ obj: ['value1', 'value2'] }

You can force creating an object by setting the arrayLimit option to 0:

Qs.parse('obj[1]=value&obj[2]=value', { arrayLimit: 0 });

which will give you:

{ obj: { '1': 'value', '2': 'value' } }