Wrong declaration AST coming out of quotation?

[mainland]

Wrong declaration AST coming out of quotation?

[mainland]

Type `help' or `?' for help
cdecl> explain void *(*foo[2])()
declare foo as array 2 of pointer to function returning pointer to void
cdecl> explain void (*foo[2])()
declare foo as array 2 of pointer to function returning void
cdecl>

The AST looks correct to me. What do you think it should be?

[deepfire]

Geoffrey, I am sorry for making the noise.

The AST does indeed correctly follow the C language quirks, where one can say

char foo = 'a', *bar = "b";

..which necessitates the split of the type and pointer information into two different places within the AST.

One can be found regretful of this complication, even if it is understandable..

Once again, sorry for the noise!