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LTLA avatar LTLA commented on June 8, 2024

It is done: 14849bf. Note that it literally just skips the simulation step, replacing the simulated doublets with the known doublets and continuing on with the same score calculation.

I toyed with the idea of allowing users to pass in a separate matrix of counts for doublets. This might still be possible but it needs careful consideration about the interaction with size.factors.norm. I suspect it will not be safe to have both a separate matrix and size.factors.norm supplied.

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LTLA avatar LTLA commented on June 8, 2024

I ended up taking out known.doublets in favor of an explicit doubletRecovery() function, to avoid the assumption of random doublet formation used in the doubletCells() score calculation. Enjoy.

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PeteHaitch avatar PeteHaitch commented on June 8, 2024

Cheers, I'll take it for a spin.

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