Comments (2)
I have never tested the make file with the shared object. I see that it is setting the flags for the standard mf6 executable.
Change the compiler and linker flags in makedefault
to
# set the fortran flags
ifeq ($(detected_OS), Windows)
ifeq ($(FC), gfortran)
FFLAGS ?= -fPIC -fbacktrace -ffpe-summary=overflow -ffpe-trap=overflow,zero,invalid $(OS_macro) -Wtabs -Wline-truncation -Wunused-label -Wunused-variable -pedantic -std=f2008 -Wcharacter-truncation -cpp
endif
else
ifeq ($(FC), gfortran)
FFLAGS ?= -fPIC -fbacktrace -ffpe-summary=overflow -ffpe-trap=overflow,zero,invalid $(OS_macro) -Wtabs -Wline-truncation -Wunused-label -Wunused-variable -pedantic -std=f2008 -Wcharacter-truncation -cpp
endif
ifeq ($(FC), $(filter $(FC), ifort mpiifort))
FFLAGS ?= -no-heap-arrays -fpe0 -traceback -fpp
MODSWITCH = -module $(MODDIR)
endif
endif
# set the ldflgs
ifeq ($(detected_OS), Windows)
ifeq ($(FC), $(filter $(FC), gfortran))
LDFLAGS ?= -shared -lm
endif
else
ifeq ($(FC), gfortran)
LDFLAGS ?= -shared -lc
endif
ifeq ($(FC), $(filter $(FC), ifort mpiifort))
LDFLAGS ?= -lc
endif
endif
This works for gfortran
but is not correct for ifort
.
I will address the makefile flags as soon as I can get to it.
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thanks @jdhughes-usgs ! It looks like its just the -shared
linker flag that is missing (duh! sorry shouldnt been able to sort that!)
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