Comments (5)
Thank you for your comment and interest! At the moment, the contrasts are indeed hard-coded to the specific style, but I will think about the possibility to allow the user to set them.
I am sorry for the missing information about the order in the default title when there is only one plot/comparison. If your test output is saved in an R object res, you can find the title that you would like to have in attr(res, "labels").
from get.
Thank you for the quick response!
Just to confirm: am I correct in thinking that multiplying obs, central, hi and lo by -1 and then exchanging lo and hi will give me the result I would have gotten if the contrast were done in the other direction?
from get.
I realise it can be a bit confusing with the different contrasts. In graph.flm, first, to obtain the regression coefficients for each group, the constrasts option "contr.sum" is used for the lm function. If you use contrasts = FALSE
, the coefficients are used as the test statistic as such. If you use constrasts = TRUE
, then differences of the coefficients are used as the test statistic. Given the coefficients in a specific order that is obtained through the use of lm and dummy.coef, the differences are taken currently by checking only couples i and j where i < j and reducing j from i. E.g. groups 1, 2, 3 leads to comparisons 1-2, 1-3, 2-3. I hope this clarifies.
from get.
Thank you! For others' reference, the workaround I discovered based on your explanation was to relevel my factor with the treatment condition as the reference level.
from get.
Hi,
this took some time, but now the function graph.flm
has a further option NULL
for the argument contrasts
. If contrasts = NULL
the coefficients given by lm
are used directly as the test statistic. (The contrasts of lm
can be controlled by options
.)
-Mari
from get.
Related Issues (7)
- Gets a nonzero liberal p-value when a zero is expected HOT 2
- Plotting of 2d envelopes broken for non-square matrices HOT 1
- graph.flm with functional covariate and contrasts=TRUE fails with error HOT 1
- nestedness checking and equivalent interactions when omitting a main effect HOT 2
- central_region always uses mean and never median as central function (at least in some cases). HOT 1
- fBoxplot: error if length(outliers_id) == 1 (line 85) HOT 13
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