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nikky4D avatar nikky4D commented on August 21, 2024 1

Check the size of the matrix/vector in x[0], if it has a 1 in the batch dimension, after squeeze in norm() function, this reduces to a vector which is problematic for the norm

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layumi avatar layumi commented on August 21, 2024

Yes @aiqiangbrave

It is due to the batch size = 1

You could use

if len(x.shape) ==2:
    x = x.unsqueeze(0)

Something like that.

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aiqiangbrave avatar aiqiangbrave commented on August 21, 2024

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aiqiangbrave avatar aiqiangbrave commented on August 21, 2024

Check the size of the matrix/vector in x[0], if it has a 1 in the batch dimension, after squeeze in norm() function, this reduces to a vector which is problematic for the norm

okok,thank you!

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