Comments (2)
Q2h1Cg
commented on August 16, 2024
接受受不了折中，速度与准确率都应该保证。
如下解决方式：
- 发现某子域名 DNS 响应不是权威 DNS 后将其父级域名的权威 DNS 保存至hash表、新建连接并枚举其
- 对接下来的子域名判断其父域名是否存在于表中，若存在则通过已有连接枚举；若不存在则进行第一步
这样可以避免对每个域名都去获取其权威 DNS，只获取一次对整体速度的影响不大。
需要修改程序整体架构，慢慢改吧，实在是改不好的时候再去考虑折中 : )
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Q2h1Cg
commented on August 16, 2024
新版本已解决
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