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rafguns avatar rafguns commented on June 22, 2024

Indeed, nodes are assumed to be all of the same type and sortable. Looking at this code again, I wonder if maybe we can just get rid of _sorted_tuple and do sth like this:

def __eq__(self, other):
    try:
        return self.elements == other.elements
    except AttributeError:
        a, b = other
        return self.elements == (a, b) or self.elements == (b, a)

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rafguns avatar rafguns commented on June 22, 2024

Fixed in 58ff2e1.

I have kept _sorted_tuple for now: it ensures that the ranking of node pairs is always the same, even in case of ties.

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