How to generate a standard ontology title?

[rbuck-som]

How to generate a standard ontology title?

[LvanWissen]

But in Turtle syntax the rdfs: translates to a valid URI.

I don't think there is a way to unbind a prefix from the NamespaceManager, which automatically binds some 'core prefixes':

rdflib/rdflib/namespace/__init__.py

Lines 463 to 464 in ce7e414

	for prefix, ns in _NAMESPACE_PREFIXES_CORE.items():
	self.bind(prefix, ns)

)

Either pick a different serialization format (e.g. nt), or write your own custom NamespaceManager. But keep in mind that the rdfs: bit is valid RDF.

[edmondchuc]

Is this what you want?

from rdflib import Graph, URIRef, Literal, RDF, OWL, DC


graph = Graph()
graph.namespace_manager.bind("rdfs", None, replace=True)

rdfs = URIRef("http://www.w3.org/2000/01/rdf-schema#")

graph.add((
    rdfs, RDF.type, OWL.Ontology
))
graph.add((
    rdfs, DC.title, Literal("The RDF Schema vocabulary (RDFS)")
))

graph.print()

Output:

@prefix dc: <http://purl.org/dc/elements/1.1/> .
@prefix owl: <http://www.w3.org/2002/07/owl#> .

<http://www.w3.org/2000/01/rdf-schema#> a owl:Ontology ;
    dc:title "The RDF Schema vocabulary (RDFS)" .

Looks like binding an existing prefix with None with the optional replace=True will "unbind" the prefix.

[rbuck-som]

Thank you!

…

On Tue, Dec 12, 2023 at 6:24 PM Edmond Chuc ***@***.***> wrote: Is this what you want? from rdflib import Graph, URIRef, Literal, RDF, OWL, DC graph = Graph()graph.namespace_manager.bind("rdfs", None, replace=True) rdfs = URIRef("http://www.w3.org/2000/01/rdf-schema#") graph.add(( rdfs, RDF.type, OWL.Ontology ))graph.add(( rdfs, DC.title, Literal("The RDF Schema vocabulary (RDFS)") )) graph.print() Output: @Prefix dc: <http://purl.org/dc/elements/1.1/> .@Prefix owl: <http://www.w3.org/2002/07/owl#> . <http://www.w3.org/2000/01/rdf-schema#> a owl:Ontology ; dc:title "The RDF Schema vocabulary (RDFS)" . Looks like binding an existing prefix with None with the optional replace=True will "unbind" the prefix. — Reply to this email directly, view it on GitHub <#2643 (comment)>, or unsubscribe <https://github.com/notifications/unsubscribe-auth/AOTAUAZ4QFSG6K67DSLUSXTYJDRT5AVCNFSM6AAAAAA7LSFMRSVHI2DSMVQWIX3LMV43OSLTON2WKQ3PNVWWK3TUHMYTQNJSHE4TCNJVGU> . You are receiving this because you authored the thread.Message ID: ***@***.***>

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