How to be sure if main thread is blocked or not?

[salomonbrys]

How to be sure if main thread is blocked or not?

[SalomonBrys]

I think you misunderstood _tick = (_tick + 1) % 10).
It means that _tick will be incremented by _one_ and then set to the result modulo ten.

So, before _uiHandler.post(_ticker), we know that _tick == lastTick, then the _ticker task will increment _tick by one and ensure that it remains within [0-10[.

• When lastTick is 0, then _ticker will (try to) set _tick to 1.
• When lastTick is 1, then _ticker will (try to) set _tick to 2.
• ...
• When lastTick is 9, then _ticker will (try to) set _tick to 0.

So, as the _ticker task is only run once between lastTick = _tick and if (_tick == lastTick), _tick can not be the same as lastTick after one _ticker execution.

The modulo 10 is because, you know, we have 10 fingers. Any modulo would have done. In truth, the actual best meaningful modulo would have been (Integer.MAX_VALUE - 1).

I did this to avoid overflow.
Granted, to overflow, with _timeoutInterval set to 5 seconds, the app would have to remain opened 340 years...

...I hope future generation will remember me fondly ;)

[PanWangJ]

Ah, the problem of me is not with the _tick = (_tick + 1) % 10, but actually what I got wrong is with the Runnable object _ticker. I thought that this Runnable object will keep running(not just once but a lot of times) in the main thread and thus change the value of _tick from 0 to 9 continuously. Anyway, thanks for your explanation, I believe this is a stupid mistake that I will bear in mind for quite a long time.
Thanks again!

[PanWangJ]

And, you are really funny about the 340 years thing :)