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Jictyvoo avatar Jictyvoo commented on July 20, 2024 1

I don't know if have any problem by linking this here, but this is the PR that I made on the DI that I work on

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Jictyvoo avatar Jictyvoo commented on July 20, 2024

I think that it's possible, but can be really slow, because we gonna try to discover all elements type that fits with the given interface. I'm a mantainer in another DI library, later today I gonna check if I can do this there.

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Jictyvoo avatar Jictyvoo commented on July 20, 2024

Yeah, that is possible to do

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GregPja avatar GregPja commented on July 20, 2024

nice! That would same me quite some manual work. At the end I found a solution where I provide the list of all dependencies, but I then need to list them manually.

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Jictyvoo avatar Jictyvoo commented on July 20, 2024

nice! That would same me quite some manual work. At the end I found a solution where I provide the list of all dependencies, but I then need to list them manually.

Looks nice, can you share a piece of code that represents it?

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GregPja avatar GregPja commented on July 20, 2024

nice! That would same me quite some manual work. At the end I found a solution where I provide the list of all dependencies, but I then need to list them manually.

Looks nice, can you share a piece of code that represents it?

type ISomething interface {
	
}

func Inject(i *do.Injector) ([]ISomething, error){
	return []ISomething{
		Impl1{}, Impl2{}, Impl3{},
	}, nil
}

func InjectService(i *do.Injector) (IService, error) {
 	return ServiceImpl{
		 somethings : do.MustInvoke[[]ISomething](i),
	}, nil
}

This is it basically. But of course it would be nicer to be able to register those ISomething one by one...
But I see also the limitation of this request. Maybe instead of having do.Provide(Inject,i) we could have an explicit do.ProvideMany and a do.MustInvokeMany that don't panic if there is more than 1 implementation

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