Shell language lexing mistakes bitwise left shift operator for here document

[echo-e]

Shell language lexing mistakes bitwise left shift operator for here document

[zufuliu]

Simplified as:

for ((i = 0; i < 2; i++)); do
  echo $(((1) << i)) # colored as shift operator
done

for ((i = 0; i < 2; i++)); do
  echo $((((1)) << i)) # colored as here-doc
done

[zufuliu]

patch to fix the bug: 215.patch

diff --git a/lexers/LexBash.cxx b/lexers/LexBash.cxx
index 157af818..199172ec 100644
--- a/lexers/LexBash.cxx
+++ b/lexers/LexBash.cxx
@@ -333,7 +333,7 @@ public:
 	}
 	bool CountDown(StyleContext &sc, CmdState &cmdState) {
 		Current.Count--;
-		if (Current.Count == 1 && sc.Match(')', ')')) {
+		while (Current.Count > 0 && sc.chNext == Current.Down) {
 			Current.Count--;
 			sc.Forward();
 		}
@@ -380,10 +380,6 @@ public:
 					sc.ChangeState(SCE_SH_BACKTICKS);
 				}
 			}
-			if (current == CmdState::Body && sc.Match('(', '(') && state == SCE_SH_DEFAULT && Depth == 0) {
-				// optimized to avoid track nested delimiter pairs
-				style = QuoteStyle::Literal;
-			}
 		} else {
 			// scalar has no delimiter pair
 			if (!setParamStart.Contains(sc.ch)) {

[nyamatongwe]

Looks good since its a simplification - committed.