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NikolausDemmel avatar NikolausDemmel commented on June 10, 2024

I think both are correct. Note that $\mathbf{a}$ in the report corresponds to omega / theta in the code. You can see the equivalence using the identity $\hat{\mathbf{a}}^2 = \mathbf{a} \mathbf{a}^\top - I$.

More practically, we have the same variant of the formula in Basalt and a unit test that verifies the Jacobian numerically.

It is my understanding that the version of the formula in the code, while analytically equivalent, has better numerics.

from sophus.

dzywater avatar dzywater commented on June 10, 2024

I think both are correct. Note that a in the report corresponds to omega / theta in the code. You can see the equivalence using the identity a^2=aa⊤−I.

More practically, we have the same variant of the formula in Basalt and a unit test that verifies the Jacobian numerically.

It is my understanding that the version of the formula in the code, while analytically equivalent, has better numerics.

Thanks. I got it.

from sophus.

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