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Comments (2)

tov avatar tov commented on May 26, 2024

Question: Which of these is E1 += E2 sugar for?

  • E1.__iadd__(E2)
  • (fake syntax for references):

    let rval = &E1
    *E1 = *E1 + E2

from dssl2.

markovejnovic avatar markovejnovic commented on May 26, 2024

Question: Which of these is E1 += E2 sugar for?

  • E1.__iadd__(E2)
  • (fake syntax for references):
    let rval = &E1
    *E1 = *E1 + E2

Personally, I think __iadd__ is the better choice. Suppose you have:

let a = [3, 4, None, None]
let b = [6, 8]

One could choose to implement:

let c = a + b
a == a # Not mutating
b == b # Not mutating
c == [3, 4, None, None, 6, 8]
a += b
a == [3, 4, 6, 8] # Mutating

Not the best design choice in my opinion, but someone might have a good reason for doing that.

from dssl2.

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