Comments (2)
KyleJune
commented on July 23, 2024
fun is asynchronous. Without awaiting it before calling the delay function that restores native time, there is a chance that native time would be restored temporarily while the code in fun is running. You could encounter a similar issue if you were to call ft.restore() after fun without awaiting it.
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meooow25
commented on July 23, 2024
I realize how it works, but my intent was to point out that someone using the library may not immediately figure out that delay/restoreFor has such a side effect. Whether this needs a fix, the choice is yours.
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