removing devDependencies

[willyg302]

removing devDependencies

[willyg302]

I tried using gulp-install but quickly gave up because it seems to install the Node modules in place and doesn't forward them down the stream, which means they won't be included in the zip. My solution was the following:

Assume a package structure like this:

src/
    index.js
    package.json
Gulpfile.js
package.json
publish.sh

The src/ directory contains your actual Lambda function package, including any dependencies needed (async, Mocha, etc.). Then there's the "outer" directory which contains the build logic. I whipped up a quick shell script -- publish.sh -- to do what I thought gulp-install would do:

rm -rf dest
cp -R src dest
cd dest && npm install --production && cd ..
gulp

And then in the Gulpfile:

gulp.task('default', function() {
    return gulp.src('dest/**/*')
        .pipe(zip('archive.zip'))
        .pipe(lambda(lambda_params, opts))
        .pipe(gulp.dest('.'));
});

Not entirely pretty, but it works. Let me know if that helps!

[matthewchung74]

Thanks for responding Willy. In this case, if Mocha is in src/ , wouldn't
that get copied up to AWS as well?

On Thu, Jul 30, 2015 at 9:48 PM, WillyG Productions <
[email protected]> wrote:

I tried using gulp-install but quickly gave up because it seems to install
the Node modules in place and doesn't forward them down the stream, which
means they won't be included in the zip. My solution was the following:

Assume a package structure like this:

src/
index.js
package.json
Gulpfile.js
package.json
publish.sh

The src/ directory contains your actual Lambda function package,
including any dependencies needed (async, Mocha, etc.). Then there's the
"outer" directory which contains the build logic. I whipped up a quick
shell script -- publish.sh -- to do what I thought gulp-install would
do:

rm -rf dest
cp -R src destcd dest && npm install --production && cd ..
gulp

And then in the Gulpfile:

gulp.task('default', function() {
return gulp.src('dest/*/')
.pipe(zip('archive.zip'))
.pipe(lambda(lambda_params, opts))
.pipe(gulp.dest('.'));
});

Not entirely pretty, but it works. Let me know if that helps!

—
Reply to this email directly or view it on GitHub
#2 (comment)
.

Regards,
Matt

[willyg302]

Oh you're right, sorry about that. The goal is to copy over to dest but exclude node_modules, which means that this command (instead of cp) should do the trick:

rsync -r src dest --exclude node_modules

[matthewchung74]

Thank you.

On Friday, July 31, 2015, WillyG Productions [email protected]
wrote:

Oh you're right, sorry about that. The goal is to copy over to dest but
exclude node_modules, which means that this command (instead of cp)
should do the trick:

rsync -r src dest --exclude node_modules

—
Reply to this email directly or view it on GitHub
#2 (comment)
.

Regards,
Matt