Comments (5)
Not sure about 0 in S1 Mode, but rssi_filter() function should definetely be duplicated for both signal paths. Will fix this tomorrow.
from rtl-wmbus.
- Just fixed the issue with rssi = 0
- rssi_filter() splitted in two functions for T1/C1 and S1
Please test.
from rtl-wmbus.
working ok now. Could you explain or link an explanation for both rssi diferences?
Thank you
alvaro@alvaro-Compaq-Presario-CQ61-Notebook-PC:~/rtl-wmbus-master$ rtl_sdr -f 868.3M -s 1600000 - 2>/dev/null | rtl_wmbus
S1;1;1;2021-02-06 12:01:30.000;140;148;04998541;0x2c4465324185990401087a008000000b6e560400426c5f0c4b6e452301326c0000046d1a0e6f0202fdac7e0123
S1;1;1;2021-02-06 12:01:52.000;146;130;04998541;0x2c4465324185990401087a008000000b6e560400426c5f0c4b6e452301326c0000046d1a0e6f0202fdac7e0123
alvaro@alvaro-Compaq-Presario-CQ61-Notebook-PC:~/rtl-wmbus-master$ rtl_sdr -f 868.7M -s 1600000 - 2>/dev/null | rtl_wmbus -s
S1;1;1;2021-02-06 12:02:35.000;137;141;04998541;0x2c4465324185990401087a008000000b6e560400426c5f0c4b6e452301326c0000046d1a0e6f0202fdac7e0123
from rtl-wmbus.
It's simple. Packet rssi is an rssi value taken at the first datagram's bit (most significant bit in the L field) and will not be updated while receiving remaining bits of the current packet (or datagram). An another rssi is the current rssi which will be continuously updated with each bit received.
It's because I want to know how rssi was changing regarding to the beginning of the packet currently received.
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