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View Code? Open in Web Editor NEWSolutions to problems from various online judges / contest sites.
License: Do What The F*ck You Want To Public License
Solutions to problems from various online judges / contest sites.
License: Do What The F*ck You Want To Public License
I have a very similar Pythonic solution to greeting card (https://open.kattis.com/problems/greetingcard) by hardcoding the only possible situations where pairs of points are exactly 2018 units apart. However, my solution failed with a "TLE" message failing on the 5/11 test case and I just couldn't figure out why.
Is your solution able to successful pass all the test cases on Kattis?
T = int(input())
lattice = []
for _ in range(T):
x, y = map(int, input().split())
lattice.append((x, y))
count = 0
for index in range(len(lattice)):
cur_x = lattice[index][0]
cur_y = lattice[index][1]
for jndex in range(index, len(lattice)):
nex_x = lattice[jndex][0]
nex_y = lattice[jndex][1]
if ((cur_x + 2018 == nex_x and cur_y == nex_y) or
(cur_x - 2018 == nex_x and cur_y == nex_y) or
(cur_x == nex_x and cur_y + 2018 == nex_y) or
(cur_x == nex_x and cur_y - 2018 == nex_y) or
# more
(cur_x + 1118 == nex_x and cur_y + 1680 == nex_y) or
(cur_x + 1118 == nex_x and cur_y - 1680 == nex_y) or
(cur_x - 1118 == nex_x and cur_y + 1680 == nex_y) or
(cur_x - 1118 == nex_x and cur_y - 1680 == nex_y) or
# more
(cur_x + 1680 == nex_x and cur_y + 1118 == nex_y) or
(cur_x + 1680 == nex_x and cur_y - 1118 == nex_y) or
(cur_x - 1680 == nex_x and cur_y + 1118 == nex_y) or
(cur_x - 1680 == nex_x and cur_y - 1118 == nex_y)):
count += 1
print(count)
I submitted the same solution you provided but it gives time limit exceeded
please recheck the solution of Common Divisors
The solution given for 1628 - Meet in the Middle gives Wrong Answer on the last test case. Kindly check the code.
CAn you please explain why this matrix was constructed in such a way
competitive-programming/cses/1096.cc
Line 38 in 1cc6c64
I know that later part will be solved by matrix exponentiation. But facing some difficulties in building the base matrix
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