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一个轻量级、高效率的支持多端(应用与硬件Iot)的可分布式、异步网络应用通讯框架

License: Apache License 2.0

Java 94.91% HTML 5.09%
asynchronous chat chat-room framework im iot mqtt netty4 tcp-ip websocket-chat

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erichetti avatar hackercat1994 avatar noseparte avatar unclecatmyself avatar

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inchat's Issues

TODO LIST

  • 1.聊天记录的数据库保存
  • 2.离线消息的推送
  • 3.文件的传输

小白请教问题

您好 我是一个android 小白,目前工作需要使用 netty + mqtt 来尝试和 客户端硬件通信,想加个 您的qq 请教一些问题?方便么

启动自带的demo出现异常了

新人,这个一场请问是怎么回事呢,没做什么修改,就改了数据库地址
2020-04-27 16:38:21.523 INFO 5192 --- [ WORK_1] c.g.u.bootstrap.handler.DefaultHandler : [DefaultWebSocketHandler.channelActive]/10.19.9.176:62643链接成功
FullHttpRequestDefaultFullHttpRequest(decodeResult: failure(java.lang.IllegalArgumentException: invalid version format: ]IÊN.8À�Z±�²ÓU =), version: HTTP/1.0, content: UnpooledByteBufAllocator$InstrumentedUnpooledUnsafeHeapByteBuf(ridx: 0, widx: 0, cap: 0))
GET /bad-request HTTP/1.0
/bad-request
2020-04-27 16:38:21.547 INFO 5192 --- [ WORK_1] c.g.u.bootstrap.handler.DefaultHandler : [DefaultWebSocketHandler.httpdoMessage.NOTFINDURI]
2020-04-27 16:38:21.549 INFO 5192 --- [ WORK_1] c.g.u.b.c.http.HttpChannelServiceImpl : [HttpChannelServiceImpl.close] 关闭HTTP通道连接
2020-04-27 16:38:21.551 INFO 5192 --- [ WORK_1] c.g.unclecatmyself.common.base.Handler : [Handler:channelInactive]0.0.0.0/0.0.0.0:8090关闭成功
2020-04-27 16:38:21.551 ERROR 5192 --- [ WORK_1] c.g.unclecatmyself.common.base.Handler : [捕获异常:NotFindLoginChannlException]-[Handler:channelInactive] 关闭未正常注册链接!
1587976733(1)

为什么每次开启新的连接,都发生异常断开呢

open ssl success
2020-04-29 10:37:19.176 INFO 13184 --- [ WORK_1] c.g.u.bootstrap.handler.DefaultHandler : [DefaultWebSocketHandler.channelActive]/10.19.9.176:55694链接成功
2020-04-29 10:37:19.206 INFO 13184 --- [ WORK_1] c.g.u.bootstrap.handler.DefaultHandler : [DefaultWebSocketHandler.exceptionCaught]/10.19.9.176:55694异常断开
2020-04-29 10:37:19.207 INFO 13184 --- [ WORK_1] c.g.unclecatmyself.common.base.Handler : [Handler:channelInactive]0.0.0.0/0.0.0.0:8090关闭成功
2020-04-29 10:37:19.207 ERROR 13184 --- [ WORK_1] c.g.unclecatmyself.common.base.Handler : [捕获异常:NotFindLoginChannlException]-[Handler:channelInactive] 关闭未正常注册链接!
2020-04-29 10:37:19.209 INFO 13184 --- [ WORK_1] c.g.u.bootstrap.handler.DefaultHandler : [DefaultWebSocketHandler.exceptionCaught]/10.19.9.176:55694异常断开
open ssl success
2020-04-29 10:37:19.272 INFO 13184 --- [ WORK_2] c.g.u.bootstrap.handler.DefaultHandler : [DefaultWebSocketHandler.channelActive]/10.19.9.176:55695链接成功
TextWebSocketFrameTextWebSocketFrame(data: PooledUnsafeDirectByteBuf(ridx: 0, widx: 31, cap: 31))
2020-04-29 10:37:19.311 INFO 13184 --- [ WORK_2] c.g.u.bootstrap.handler.DefaultHandler : [DefaultWebSocketHandler.textdoMessage.LOGIN]

demo的发送图片功能貌似是有问题嗷

TextWebSocketFrameTextWebSocketFrame(data: PooledUnsafeDirectByteBuf(ridx: 0, widx: 50, cap: 50))
2020-04-28 09:59:54.817 INFO 9572 --- [ WORK_2] c.g.u.bootstrap.handler.DefaultHandler : 图片到个人
1111
{}
2020-04-28 09:59:54.828 INFO 9572 --- [ WORK_2] c.g.u.bootstrap.handler.DefaultHandler : [DefaultWebSocketHandler.exceptionCaught]/10.19.9.176:53046异常断开
2020-04-28 09:59:54.832 INFO 9572 --- [ WORK_2] c.g.unclecatmyself.common.base.Handler : [Handler:channelInactive]0.0.0.0/0.0.0.0:8090关闭成功

服务端 用户上下线通知

用户上线时需要 获取未读的消息,未读信息可以自己业务里处理,需要框架提供用户上线通知方法。
用户下线时需要 告诉系统自己是下线状态,同用户上线一致

http三个接口请求路径地址名字不一致

比如服务器端推送 send_from_server,为什么还有一个/uri_send_from_server。
看了你的版本介绍1.1.2的使用,截图也是用:[ip:端口]/send_from_server (POST请求),
实际我测试使用发现使用[ip:端口]/uri_send_from_server才行,是我哪里用错了吗?
正在学习,我新手想问下,在controller层中调用send_from_server能进行服务端推送吗?

wss未能正常连接

@UncleCatMySelf

use isSSL=true
使用chrome浏览器客户端未显示不安全的链接,导致添加不了证书。

`
open ssl success
INFO - [DefaultWebSocketHandler.channelActive]/10.0.75.1:55663链接成功
INFO - [DefaultWebSocketHandler.exceptionCaught]/10.0.75.1:55663异常断开
INFO - [Handler:channelInactive]0.0.0.0/0.0.0.0:8070关闭成功
ERROR - [捕获异常:NotFindLoginChannlException]-[Handler:channelInactive] 关闭未正常注册链接!
INFO - [DefaultWebSocketHandler.exceptionCaught]/10.0.75.1:55663异常断开

`

服务端 判断用户是否在线

服务端 根据token判断用户是否在线方法
使用场景,当在线用户a发送信息给 离线用户b
后台需要判断b用户是否在线,如果不在线则把消息写到数据库中,并且标注为未读信息。
当用户上线时,读取自己的未读消息,进行查阅。

【项目组】未来InChat的项目形式讨论

inchat将发布1.1.5版本,作为作者,我也有了一些不同的想法,希望各位朋友可以给出你们工作中或者使用中的一些建议。

1、以Maven包的形式,集成的自己项目内部

  • 框架不集成SpringBoot等web框架
  • 数据存储的形式较为麻烦
  • 需要了解框架的api

2、以独立项目的形式,开箱即用的即时通信IM

pom.xml 版本号抽取

<properties> <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding> <project.reporting.outputEncoding>UTF-8</project.reporting.outputEncoding> <java.version>1.8</java.version> <redis.clients.version>3.0.1</redis.clients.version> <slf4j.version>1.7.25</slf4j.version> <fastjson.version>1.2.53</fastjson.version> <gson.version>2.8.5</gson.version> <netty.version>4.1.32.Final</netty.version> <commons.lang3.version>3.0.1</commons.lang3.version> </properties>

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