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omrilotan avatar omrilotan commented on April 28, 2024 7

Couldn't find a resolution for this. This is how I addressed this issue, if it helps the next poor soul:

In this example, the same route fails the first time, then succeeds for subsequent requests. This logic can be expanded to check anything from authentication flow to rate limit

// Initial setup
class MockResponse {
  constructor() {
    this.iterations = 0;
  }
  get response() {
    this.iterations++;
    return this.iterations === 1 ? 'Forbidden' : 'Allowed';
  }
  get status() {
    return this.iterations === 1 ? 403 : 200;
  }
}

// Register in beforeEach
moxios.stubRequest('/route', new MockResponse());

// First call fails: gets 403
expect(axios.get('/route')).rejects.toThrow('Request failed with status code 404');

// The next one's okay: gets 200
const { status } = await axios.get(REQUEST_PERIMETERX_BLOCK);
expect(status).toBe(200);

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mrchief avatar mrchief commented on April 28, 2024 3

For the time being, I'm using axios-mock-adapter and this works:

    mock.onGet('/to/no/where').replyOnce(401, mockApiError)
      .onGet('/to/no/where').replyOnce(200, mockApiResponse)

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veryneatperson avatar veryneatperson commented on April 28, 2024 1

omrilotan, thanks a lot.
Kinda hard to find reasonable solutions for that.
It really works (even though feels kinda unnatural).

By the way, as i understand, moxios.stubRequest first calls get response and then get status.

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omrilotan avatar omrilotan commented on April 28, 2024 1

@veryneatperson You're right

moxios/index.js

Lines 268 to 269 in 3785075

this.data = res.responseText || res.response;
this.status = res.status

I'll switch them in the comment

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Peter-Hudson avatar Peter-Hudson commented on April 28, 2024 1

Slightly different take:

// different responses
function* responses() {
        yield { status: 401, response: { description: 'errored' } };
        yield { status: 200, response: { description: 'success' } };
      }

      const gen = responses();
     
      moxios.stubRequest('/route', gen.next().value);

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anilanar avatar anilanar commented on April 28, 2024

Kamino cloned this issue to anilanar/moxios

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