🍓 一个爱写代码的旅游爱好者。
cdoco / learn-regex-zh Goto Github PK
View Code? Open in Web Editor NEW:cn: 翻译: 学习正则表达式的简单方法
License: MIT License
:cn: 翻译: 学习正则表达式的简单方法
License: MIT License
假如有这么个字符串:2020年8月15日我来到了北京,想起了2013年的事情,现在已经是9时43分了。用正则怎么抽出["2020年8月15日", "2013年”, "9时43分”]? 即:我想抽出某个字符串中的日期和时间,但是不期望得到["2020年", "8月", "15日", "2013年", "9时", "43分"]?
是不是要介绍下 ?:
https://github.com/cdoco/learn-regex-zh/blame/master/README.md#L21
”jo-hn_doe 和 john12_as “处的下划线不需要转义,应移除反斜杆。
del
匹配最下面字符串内容:
匹配示例:
<string name="app_name" >测试应用</string>
<string name="key1">测试内容</string>
以下都要匹配上,总计匹配上五个。
我写了以下正则:
<string[ ]*name="(.*)"[ ]*>(.)*</string>
除了带换行那个都ok
<string[ ]*name="(.*)"[ ]*>(.\n)*</string>
无任何效果
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2.4花括号实例那里
"[0-9]{2}" => The number was 9.9997 but we rounded it off to 10.0.
这里匹配的应该只有后面的10吧
获取$ 字符之前,应该都是获取之后
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