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【sql 】按字段指定值order by
一、Access
使用IIF函数实现。
SELECT 表1.id, 表1.n
FROM 表1
ORDER BY IIF(n='a3',1,IIF(n='a2',2,IIF(n='a1',3,)));
未解决问题:
1.最里层假值大于3时,1的那项会排在最后面(实际应该排序正常才是,目前只能不填或填最小值);
2.未在指定值的会排在前面,如何让它们排在后面(由于1的影响,asc或desc都实现不了)?
二、Mysql
使用case函数实现。
SELECT 表1.id, 表1.n
FROM 表1
ORDER BY
CASE n
WHEN 'a2' THEN 1
WHEN 'a1' THEN 2
WHEN 'a3' THEN 3
ELSE 4 END;
实现效果,排序为a2 a1 a3,其他值排在后面.
三、Oracle
使用decode函数或case函数实现。
1、Decode
Decode(value,if1,then1,if2,then2,if3,then3.......,else6)
2、Case
select * from person order by case person_key when 4 then 1 when 5 then 2 when 6 then 3 when 7 then 4 end
Oracle没测试,不说什么。
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