harthur/clustering

K-means and hierarchical clustering

clustering's Issues

Why isn't the ultrametric distance passed in the result?

As stated, why isn't it passed into the result? This is required for displaying the results in a dendrogram.

infinite loop occured while using kmeans on a dataset with 700 datapoints

I'd love to give more details . movement is always true... (inside the loop it ofcourse false, but then changes to true)...

not sure how to fix it, really problematic.
help is needed.
It might be because of a local minima point. I've added an iterations limit to the while, so while(movement && (iterations < max_iteratoins)){ ... }

this isn't a good solution obviously, but im not familiar with the algorithm
http://blog.endava.com/k-means-clustering-algorithm
" However, in this form, there is a risk to get stuck in a local minima. By local minima I mean the local minima of the cost function:"

Please explain the meaning of the last two parameters of the keans function。

function kmeans(points, k, distance, snapshotPeriod, snapshotCb) {}

add kmeans.distance api

since kmeans.classify is provided, can you add kmeans.distance() api for deep use.

Thanks!

different runs of k-means clustering result in different outputs

var colors = [
   [97],
   [1],
   [53],
   [79],
   [3],
   [351],
   [16]
];

var clusters = clusterfck.kmeans(colors, 3);

Result A: [1, 3, 16], [53, 79, 97], [351]
Result B: [1, 3, 16, 53], [79, 97], [351]

A couple of things I'd like to add

I have two features I'd like to add to hcluster, but I thought I'd run them by you before I ran off and built them. They are:

1. Make it possible to directly provide my own distance matrices, instead of the features and distance measure. One thing I really like about hierarchical clustering is that you can use sets of distances that don't make sense in any space, so I'd like to leverage that like I can in SciPy. I'd love a suggestion on what the interface should look like though.
2. Add Ward's linkage as a linkage option. The complication there is that it doesn't fit neatly into the existing code because it can't be computed for each cluster independently. (Also it looks hard and I'm bad at math, but I'll get there.)

What do you think?

Can I i have an identification item that can be ignored by clusterfck.kmeans

For example the first item is an identification item ( userid ) so that I can know who went in wich cluster.

var colors = [
   ['a1',20, 20, 80],
   ['a2',22, 22, 90],
   ['a3',250, 255, 253],
   ['a4',0, 30, 70],
   ['a5',200, 0, 23],
   ['a6',100, 54, 100],
   ['a7',255, 13, 8]
];
clusterfck.kmeans(colors, 3);

If I run this it just hungs. Is there a way to ignore the first item, and just consider the rest?

Thanks

kmeans on spark error: requires number of clusters greater than one, but does not respond to changing 'k'

I have this code:

val fileName = """file:///home/user/data/csv/sessions_sample.csv"""
     val df = spark.read.format("csv").option("header", "true").option("inferSchema", "true").load(fileName)
     val input1 = df.select("id", "duration", "ip_dist", "txr1", "txr2", "txr3", "txr4").na.fill(3.0)
     val input2 = input1.map(r => (r.getInt(0), Vectors.dense((1 until r.size - 1).map{ i =>  r.getDouble(i)}.toArray[Double])))
     val input3 = input2.toDF("id", "features")
     input3.count()

val kmeans = new KMeans().setK(100).setSeed(1L).setFeaturesCol("features").setPredictionCol("prediction")
val model = kmeans.fit(input3)
val model = kmeans.fit(input3.select("features"))
// Make predictions
val predictions = model.transform(input3.select("features"))
val predictions = model.transform(input3)
val evaluator = new ClusteringEvaluator()
// i get error when i run this line
val silhouette = evaluator.evaluate(predictions)

Error: 

> java.lang.AssertionError: assertion failed: Number of clusters must be greater than one.
>   at scala.Predef$.assert(Predef.scala:170)
>   at org.apache.spark.ml.evaluation.SquaredEuclideanSilhouette$.computeSilhouetteScore(ClusteringEvaluator.scala:416)
>   at org.apache.spark.ml.evaluation.ClusteringEvaluator.evaluate(ClusteringEvaluator.scala:96)
>   ... 49 elided


Of course i tried changing k. It does not respond. On top of that, I have clusters with infinite cluster centers. For absolutely no value of k my clusters are stable => silhouette gives weird error?

`model.clusterCenters.foreach(println)`

> [3217567.1300936914,145.06533614203505,Infinity,Infinity,Infinity]


please advise. 

Record distance value when linking hierarchical clusters

It'd be a nice improvement if there was a way to access the distance between the left and right subtrees of the resulting hierarchical clustering tree without having to re-run the distance function. Perhaps this information could be recorded in the canonical object. This would make it easier (and cheaper) to generate an arbitrary number of clusters from the tree instead of just decending the tree to some depth to generate 2^depth clusters.

It would be even better if there was a function bound to the result of hcluster that accepted some int number of clusters and output the clusters in a list.

Update http://harthur.github.io/clusterfck/

Update http://harthur.github.io/clusterfck/. It's stating to use:

var clusters = clusterfck.hcluster(colors, clusterfck.EUCLIDEAN_DISTANCE, clusterfck.AVERAGE_LINKAGE, threshold);

Instead of:

var tree = clusterfck.hcluster(colors, "euclidean", "single");

Or even better, remove http://harthur.github.io/clusterfck/