data_3.05_activities's People
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bcarrero catarinamcbatista cornettomlette sogunmola ferrazzolidicreddo drhech macarenagortazar jast92 sdbrugman saranme izelyekrek kevinspurk elissadejong kaylabolden filiklik jecastrom grovyle12 maiapozzolo faezehsadatm leonardoolmos laurachavez8 aguvazsan alejandradelga claudegaresdata_3.05_activities's Issues
solution too complex
the offered solution is too complex as it refers to multiple tables.
this question can be answered by a simpler method using just the trans table :
select floor(avg(numtrans)) from
(select account_id, count(trans_id) as numtrans
from trans
group by account_id) q1
select account_id, count(trans_id) as numtrans
from trans
group by account_id
having numtrans > (
select floor(avg(numtrans)) from
(select account_id, count(trans_id) as numtrans
from trans
group by account_id) q1
)
#step 1 - identify the no of trans per account using a group by inner query
#step 2 get the avg of that query as a temp table inside the query. answer 192
#step 3 using the same group by query again, add a having clause and we will end up with only those accounts with a higher no of trans than the avg
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