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View Code? Open in Web Editor NEWJiGuang's officially supported Java client library for accessing JMessage APIs. 极光官方支持的 Java 版本服务器端 SDK。
Home Page: https://docs.jiguang.cn
License: MIT License
JiGuang's officially supported Java client library for accessing JMessage APIs. 极光官方支持的 Java 版本服务器端 SDK。
Home Page: https://docs.jiguang.cn
License: MIT License
UserStateListResult[] results = client.getUsersState("user1", "user2", "user3");
package cn.jmessage.api.user;
import cn.jiguang.common.resp.BaseResult;
import com.google.gson.annotations.Expose;
import java.util.ArrayList;
import java.util.List;
public class UserStateListResult extends BaseResult {
@Expose List<Device> devices = new ArrayList<Device>();
@Expose String username;
public String getUsername() {
return this.username;
}
private class Device {
@Expose boolean login;
@Expose boolean online;
@Expose String platform;
public boolean getLogin() {
return this.login;
}
public boolean getOnline() {
return this.online;
}
public String getPlatform() {
return this.platform;
}
}
}
@expose List devices = new ArrayList();
没有get怎么获取 还有Device 私有化 没办法获取
我们的后台上JMessageClient 只需要实例化一个吗?可以采取单例模式吗?如果采用单例模式性能如何
sendMessage时,如何设置需要回执?
只找到了单个删除用户的接口
项目还在维护吗?
sendSingleTextByAdmin发送消息成功(Response Content - { "msg_id": 3103633208,"msg_ctime":1553494488520}),app端收不到消息,控制台直推消息,app能接收到消息。
java.lang.IllegalArgumentException: The parameter username contains illegal character, a-zA-Z_0-9.、-,@。 is legally, and start with alphabet or number. Input is 中文
推送消息无法发送扩展型消息
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