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第2题:实现一个 pipe 函数,接收若干个 function,使得前一个函数的调用结果是后一个函数的参数,最后返回一个 function
实现一个 pipe 函数,接收若干个 function,使得前一个函数的调用结果是后一个函数的参数,最后返回一个 function
/****** 用例 1:******/
const process = pipe(JSON.stringify, console.log);
process({ a: 1 });
// {"a": 1}
/****** 用例 2:******/
const process = pipe(Math.max, x => x ** 2 );
process(3, 4);
// 16
function pipe(...restFns) {
const tag = Symbol('tag');
return (...args) => {
return restFns.reduce((pre, cur) => {
if (pre[tag]) return cur(...pre.args);
else return cur(pre);
}, { args, [tag]: true });
};
}
// 如果入参只有一个,则以上函数简化如下
const pipe = (...resFns) => arg => resFns.reduce((pre, cur) => cur(pre), arg);
第1题:给定一个非空整数数组,找出只出现过一次的元素?
给定一个非空整数数组,找出只出现过一次的元素,比如:
输入:[1, 2, 3, 4, 1, 2, 3] 输出:[3]
function receive(arr = []) {
const loopSet = new Set();
const cacheSet = new Set();
for (let len = arr.length; len --; ) {
const cur = arr[len];
if (!loopSet.has(cur)) { // 如果 set 中不存在说明第一次出现
loopSet.add(cur); // 第一次出现则两个 set 中都记录
cacheSet.add(cur);
} else { // 说明再次出现,从 cacheSet 中删除
cacheSet.delete(cur);
}
}
return Array.from(cacheSet);
}
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