lhelwerd/expression-parser

Python sandboxed expression parser

expression-parser's Issues

Getting error with expression evaluating a string

For my sample code, I have the following:

import expression
parser = expression.Expression_Parser()

this line below

print(parser.parse("( 1 < 1) and ('AB' == 'US') or 'userval1' != 'UPS'"))

returns this error

( 1 < 1) and ('AB' == 'US') or 'userval1' != 'UPS'
^
SyntaxError: Node Str(s='AB') not allowed

#The line below works as pure python
print(( 1 < 1 and 'US' == 'US') or 'userval1' != 'UPS')

Does the code not allow the evaluation of strings?