Comments (4)
iPhone X
focal_pix = (max( w, h ) * focal_mm) / ccdw_mm
focal_pix = 4032 pixel * 4 mm / 4.80 mm == 3360 pixel ? --> but what to do with this value?
focal_pix: the focal length in pixels,
focal_mm: the EXIF focal length (mm),
w,h the image of width and height (pixels),
ccdw_mm: the known sensor width size (mm).
CameraMaker;CameraModel;SensorWidth(mm)
Apple;iPhone 4;4.54
Apple;iPhone 4S;4.54
Apple;iPhone 5;4.54
Apple;iPhone 5S;4.89
Apple;iPhone 6;4.89
Apple;iPhone 6 Plus;4.89
from camerasensorsizedatabase.
I am comparing all the iPhone and trying to get some numbers to work with the formula, it's really confusing at the moment:
CameraMaker;CameraModel;SensorDescription;SensorWidth(mm);SensorHeight(mm),SensorWidth(pixels),SensorHeight(pixels)
Apple;iPhone 4;"1/3.2"" (~ 4.54 × 3.42 mm);4.54;3.42;2592;1936
Apple;iPhone 4S;"1/3.2"" (~ 4.54 × 3.42 mm);4.54;3.42;3264;2448
Apple;iPhone 5;"1/3.2"" (~ 4.54 × 3.42 mm);4.54;3.42;3264;2448
Apple;iPhone 5S;"1/3"" (~ 4.89 × 3.67 mm);4.89;3.67;3264;2448
Apple;iPhone 6;"1/3"" (~ 4.89 × 3.67 mm);4.89;3.67;3264;2448
Apple;iPhone 6 Plus;"1/3"" (~ 4.89 × 3.67 mm);4.89;3.67;3264;2448
from camerasensorsizedatabase.
Searching around Google, I got an arbitrary guess that iPhone X is 4.8mm?
@pmoulon
I think the sensor size is 1/3" so 4.80 mm must be the sensor width.According your metadata, it gives Fpix = std::max ( width, height ) * focalmm / ccdw = 3291 = 4032 * 4 / 4.9Internet seems confused and cannot decide if the sensor size is 1/2.8" or 1/3"
https://forums.macrumors.com/threads/8-8-x-has-the-same-sensor-size-1-3-as-6-6-where-is-the-promoted-improvement.2071530/page-4https://www.gsmarena.com/apple_iphone_x-8858.php
In my previous test, I am using value of 4.0 from focal length and Regard3D still process it, although not sure about the accuracy.
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@enzyme69 hey,have you finished your work? I want to use openmvg to deal with my photo captured with Iphone 7 PLUS,but i meet the same problem
from camerasensorsizedatabase.
Related Issues (3)
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