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paarthenon avatar paarthenon commented on May 26, 2024

Hi there! Could you let me know what version of TypeScript and Variant this is referencing? I'm using Variant 2.1 with TS 4.1 and I am experiencing a compiler error on the last line as you might expect.

Type '{ type: "cat"; }' is not assignable to type '{ type: "dog"; }'.ts(2345)

Full error:

Argument of type '(dog: { type: "dog"; }) => SumType<{ dog: VariantCreator<"dog", () => {}, "type">; cat: VariantCreator<"cat", () => {}, "type">; }, "type">' is not assignable to parameter of type '(value: SumType<{ dog: VariantCreator<"dog", () => {}, "type">; cat: VariantCreator<"cat", () => {}, "type">; }, "type">, index: number, array: SumType<...>[]) => SumType<...>'.
  Types of parameters 'dog' and 'value' are incompatible.
    Type 'SumType<{ dog: VariantCreator<"dog", () => {}, "type">; cat: VariantCreator<"cat", () => {}, "type">; }, "type">' is not assignable to type '{ type: "dog"; }'.
      Type '{ type: "cat"; }' is not assignable to type '{ type: "dog"; }'.ts(2345)

If you are indeed using these same versions, it might be a compiler caching issue. If you are using VS Code could you try ctrl+shift+P and then select the TypeScript: Restart TS Server option. There should be a similar option for other editors.

Thanks for trying out the library. I hope we can get this figured out.

from variant.

hellos3b avatar hellos3b commented on May 26, 2024

I'm on Variant 2.1.0 and TS 4.2.3 on VSCode

I've also got an example of it on code sandbox: https://codesandbox.io/s/typescript-forked-gjgvk?file=/src/index.ts:283-284

I've tried using Extract and a direct ref too with the same issue

declare function bark(dog: Extract<typeof Animal, {type: "dog"}>): Animal;
declare function bark(dog: typeof Animal.dog): Animal;

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paarthenon avatar paarthenon commented on May 26, 2024

I believe this has to do with the strictFunctionTypes tsconfig flag.

https://www.typescriptlang.org/tsconfig#strictFunctionTypes

More context: https://www.typescriptlang.org/docs/handbook/release-notes/typescript-2-6.html#strict-function-types

Enabling that flag in your code sandbox looks like it will raise the error. I tend to run with "strict": true, which will include it.

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hellos3b avatar hellos3b commented on May 26, 2024

Ah, sweet! Always forget about that setting, thanks for reminding me.

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