Django JSON-RPC 2.0

Requirements

Python 2.6 +
Django 1.4 +

Example Usage

A basic example looks like::

# foo_app/api.py
from jsonrpc.service import JSONRPCService
from jsonrpc.decorators import jrpc


class FooAPI(JSONRPCService):
    # Call all API methods with `request` as the first argument
    provide_request = True

    @jrpc('get_sum(foo=<num>, bar=<num>?) -> <num>')
    def get_sum(self, request, foo, bar=2):
        """
        No magic here, just a normal method.
        """
        return foo + bar

    def some_non_public_method(self):
        """
        Only explicitly exposed methods are exposed, so you can do what you
        want elsewhere.
        """
        ... perform top secret tasks here :)

# urls.py
# =======
from django.conf import settings
from django.views.decorators.csrf import csrf_exempt
from foo_app.api import FooAPI


foo_api = FooAPI(debug=settings.DEBUG)

urlpatterns = patterns('',
    url(r'^foo.json$', csrf_exempt(foo_api), name='foo_api'),
)

# Example POST to /foo_app/foo.json

REQ -> {"jsonrpc": "2.0", "method": "get_sum", "params": {"foo": 3}, "id": 1}

RES <- {"jsonrpc": "2.0", "result": 5, "id": 1}

# In GET requests, the JSON-RPC over HTTP spec calls for arguments to be
# provided in a format like ?params=<params>&method=<method>. Since there
# is no spec for JSON-RPC 2.0 over HTTP, I've taken some liberties and made
# things a bit simpler, allowing you to simply URL encode the exact same
# JSON request object that you'd otherwise POST to the server, and provide
# it in a "json" query param (e.g. ?json={...).

# Example GET

REQ -> /rpc.json?json=%7b%22jsonrpc%22%3a+%222.0%22%2c+%22method%22%3a+%22a
                 dd_ints%22%2c+%22params%22%3a+%5b50%2c+25%5d%2c+%22id%22%3
                 a+1%7d
RES <- {"jsonrpc": "2.0", "result": 75, "id": 1}

# Example GET, with padding (ie, JSONP)

REQ -> /rpc.json?json=%7b%22jsonrpc%22%3a+%222.0%22%2c+%22method%22%3a+%22a
                 dd_ints%22%2c+%22params%22%3a+%5b50%2c+25%5d%2c+%22id%22%3
                 a+1%7d&jsoncallback=mycallback
RES < - mycallback({"jsonrpc": "2.0", "result": 75, "id": 1})

That's it. You don't need to do anything special, define a queryset method, register anything, etc. Just write normal methods, and wrap the ones you wish to expose with the @jrpc decorator (as shown above). If you define a method and wrap it in @jrpc and the syntax of the method signature you provide to @jrpc is incorrect, it'll raise an error (during "compile" time).

Features

When your API is in debug mode you'll receive a debug key in the response JSON object, which contains information about the queries that were run during the request cycle, and tracebacks for exceptions.

Access the request by setting provide_request to True on your service class. Then, write your API methods to accept request as the first argument.

Supports JSON-P, with any callback name you'd like to use, with an attribute padding_names on your API class (default is ('callback', 'jsoncallback'))

Freebies

Every API you create comes with a method called system.describe which returns a JSON-RPC 2.0 spec description of the API's methods, the arguments they take, whether each argument is optional, which type the argument should be, etc. This method can be overridden just like any other.

:author: Michael Angeletti 📅 2013/01/24

pombredanne / django-json-rpc-2.0 Goto Github PK